(3m^2-2)-8m^2+12m-m=0,2m

Solution for (3m^2-2)-8m^2+12m-m=0,2m equation:

(3m^2-2)-8m^2+12m-m=0.2m

We move all terms to the left:

(3m^2-2)-8m^2+12m-m-(0.2m)=0

We add all the numbers together, and all the variables

-8m^2+(3m^2-2)+12m-m-(+0.2m)=0

We add all the numbers together, and all the variables

-8m^2+11m+(3m^2-2)-(+0.2m)=0

We get rid of parentheses

-8m^2+3m^2+11m-0.2m-2=0

We add all the numbers together, and all the variables

-5m^2+10.8m-2=0

a = -5; b = 10.8; c = -2;
Δ = b2-4ac
Δ = 10.82-4·(-5)·(-2)
Δ = 76.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10.8)-\sqrt{76.64}}{2*-5}=\frac{-10.8-\sqrt{76.64}}{-10}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10.8)+\sqrt{76.64}}{2*-5}=\frac{-10.8+\sqrt{76.64}}{-10}
$